Fix scrape interval length calculation
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1a3253e8ed
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@ -235,9 +235,12 @@ func (sl *scrapeLoop) run(interval, timeout time.Duration, errc chan<- error) {
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scrapeCtx, _ = context.WithTimeout(sl.ctx, timeout)
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scrapeCtx, _ = context.WithTimeout(sl.ctx, timeout)
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)
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)
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targetIntervalLength.WithLabelValues(interval.String()).Observe(
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// Only record after the first scrape.
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float64(time.Since(last)) / float64(time.Second), // Sub-second precision.
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if !last.IsZero() {
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)
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targetIntervalLength.WithLabelValues(interval.String()).Observe(
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float64(time.Since(last)) / float64(time.Second), // Sub-second precision.
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)
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}
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samples, err := sl.scraper.scrape(scrapeCtx, start)
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samples, err := sl.scraper.scrape(scrapeCtx, start)
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if err == nil {
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if err == nil {
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