Fix scrape interval length calculation

This commit is contained in:
Fabian Reinartz 2016-02-25 14:05:42 +01:00
parent 1a3253e8ed
commit fbe251c2df

View File

@ -235,9 +235,12 @@ func (sl *scrapeLoop) run(interval, timeout time.Duration, errc chan<- error) {
scrapeCtx, _ = context.WithTimeout(sl.ctx, timeout)
)
targetIntervalLength.WithLabelValues(interval.String()).Observe(
float64(time.Since(last)) / float64(time.Second), // Sub-second precision.
)
// Only record after the first scrape.
if !last.IsZero() {
targetIntervalLength.WithLabelValues(interval.String()).Observe(
float64(time.Since(last)) / float64(time.Second), // Sub-second precision.
)
}
samples, err := sl.scraper.scrape(scrapeCtx, start)
if err == nil {