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promql: refactor: initialize aggregation before storing in map

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This seems more consistent to me.

Signed-off-by: Bryan Boreham <bjboreham@gmail.com>
This commit is contained in:
Bryan Boreham 2024-01-17 10:57:02 +00:00
parent 29244fb841
commit e5f667537c
1 changed files with 9 additions and 9 deletions
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18
promql/engine.go
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@ -2686,9 +2686,6 @@ func (ev *evaluator) aggregation(e *parser.AggregateExpr, grouping []string, par
newAgg.groupCount = 0
}
result[groupingKey] = newAgg
orderedResult = append(orderedResult, newAgg)
inputVecLen := int64(len(vec))
resultSize := k
switch {
@ -2699,22 +2696,25 @@ func (ev *evaluator) aggregation(e *parser.AggregateExpr, grouping []string, par
}
switch op {
case parser.STDVAR, parser.STDDEV:
result[groupingKey].floatValue = 0
newAgg.floatValue = 0
case parser.TOPK, parser.QUANTILE:
result[groupingKey].heap = make(vectorByValueHeap, 1, resultSize)
result[groupingKey].heap[0] = Sample{
newAgg.heap = make(vectorByValueHeap, 1, resultSize)
newAgg.heap[0] = Sample{
F: s.F,
Metric: s.Metric,
}
case parser.BOTTOMK:
result[groupingKey].reverseHeap = make(vectorByReverseValueHeap, 1, resultSize)
result[groupingKey].reverseHeap[0] = Sample{
newAgg.reverseHeap = make(vectorByReverseValueHeap, 1, resultSize)
newAgg.reverseHeap[0] = Sample{
F: s.F,
Metric: s.Metric,
}
case parser.GROUP:
result[groupingKey].floatValue = 1
newAgg.floatValue = 1
}
result[groupingKey] = newAgg
orderedResult = append(orderedResult, newAgg)
continue
}