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promql: Add more test cases for `histogram_quantile` 

This is motivated by the doubts raised in #7970.

Signed-off-by: beorn7 <beorn@grafana.com>
This commit is contained in:
beorn7 2021-10-20 16:13:36 +02:00
parent 1043d2b594
commit c00c6ed01f
1 changed files with 28 additions and 0 deletions
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28
promql/testdata/histograms.test vendored
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@ -15,6 +15,15 @@ load 5m
testhistogram_bucket{le="0.3", start="negative"} 0+2x10 testhistogram_bucket{le="0.3", start="negative"} 0+2x10
testhistogram_bucket{le="+Inf", start="negative"} 0+3x10 testhistogram_bucket{le="+Inf", start="negative"} 0+3x10
# Another test histogram, where q(1/6), q(1/2), and q(5/6) are each in
# the middle of a bucket and should therefore be 1, 3, and 5,
# respectively.
load 5m
testhistogram2_bucket{le="0"} 0+0x10
testhistogram2_bucket{le="2"} 0+1x10
testhistogram2_bucket{le="4"} 0+2x10
testhistogram2_bucket{le="6"} 0+3x10
testhistogram2_bucket{le="+Inf"} 0+3x10
# Now a more realistic histogram per job and instance to test aggregation. # Now a more realistic histogram per job and instance to test aggregation.
load 5m load 5m
@ -91,6 +100,25 @@ eval instant at 50m histogram_quantile(0.8, rate(testhistogram_bucket[5m]))
{start="positive"} 0.72 {start="positive"} 0.72
{start="negative"} 0.3 {start="negative"} 0.3
# Want results exactly in the middle of the bucket.
eval instant at 7m histogram_quantile(1./6., testhistogram2_bucket)
{} 1
eval instant at 7m histogram_quantile(0.5, testhistogram2_bucket)
{} 3
eval instant at 7m histogram_quantile(5./6., testhistogram2_bucket)
{} 5
eval instant at 47m histogram_quantile(1./6., rate(testhistogram2_bucket[15m]))
{} 1
eval instant at 47m histogram_quantile(0.5, rate(testhistogram2_bucket[15m]))
{} 3
eval instant at 47m histogram_quantile(5./6., rate(testhistogram2_bucket[15m]))
{} 5
# Aggregated histogram: Everything in one. # Aggregated histogram: Everything in one.
eval instant at 50m histogram_quantile(0.3, sum(rate(request_duration_seconds_bucket[5m])) by (le)) eval instant at 50m histogram_quantile(0.3, sum(rate(request_duration_seconds_bucket[5m])) by (le))
{} 0.075 {} 0.075