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promql: store labels per-group only for count_values
This saves memory in other kinds of aggregation. We don't need `orderedResult` in `aggregationCountValues`; the ordering is not guaranteed. Signed-off-by: Bryan Boreham <bjboreham@gmail.com>
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185290a0d2
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@ -2730,7 +2730,6 @@ func vectorElemBinop(op parser.ItemType, lhs, rhs float64, hlhs, hrhs *histogram
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type groupedAggregation struct {
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hasFloat bool // Has at least 1 float64 sample aggregated.
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hasHistogram bool // Has at least 1 histogram sample aggregated.
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labels labels.Labels
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floatValue float64
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histogramValue *histogram.FloatHistogram
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floatMean float64
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@ -3044,8 +3043,11 @@ func (ev *evaluator) aggregationK(e *parser.AggregateExpr, k int, inputMatrix Ma
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// aggregationK evaluates count_values on vec.
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// Outputs as many series per group as there are values in the input.
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func (ev *evaluator) aggregationCountValues(e *parser.AggregateExpr, grouping []string, valueLabel string, vec Vector, enh *EvalNodeHelper) (Vector, annotations.Annotations) {
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result := map[uint64]*groupedAggregation{}
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orderedResult := []*groupedAggregation{}
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type groupCount struct {
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labels labels.Labels
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count int
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}
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result := map[uint64]*groupCount{}
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var buf []byte
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for _, s := range vec {
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@ -3062,24 +3064,21 @@ func (ev *evaluator) aggregationCountValues(e *parser.AggregateExpr, grouping []
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group, ok := result[groupingKey]
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// Add a new group if it doesn't exist.
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if !ok {
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newAgg := &groupedAggregation{
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labels: generateGroupingLabels(enh, metric, e.Without, grouping),
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groupCount: 1,
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result[groupingKey] = &groupCount{
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labels: generateGroupingLabels(enh, metric, e.Without, grouping),
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count: 1,
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}
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result[groupingKey] = newAgg
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orderedResult = append(orderedResult, newAgg)
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continue
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}
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group.groupCount++
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group.count++
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}
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// Construct the result Vector from the aggregated groups.
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for _, aggr := range orderedResult {
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for _, aggr := range result {
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enh.Out = append(enh.Out, Sample{
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Metric: aggr.labels,
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F: float64(aggr.groupCount),
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F: float64(aggr.count),
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})
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}
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return enh.Out, nil
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