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use count=0 instead of 1 for recursive mutex with only one lock reference
this simplifies the code paths slightly, but perhaps what's nicer is that it makes recursive mutexes fully reentrant, i.e. locking and unlocking from a signal handler works even if the interrupted code was in the middle of locking or unlocking.
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@ -30,8 +30,6 @@ int pthread_mutex_trylock(pthread_mutex_t *m)
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if ((own && !(own & 0x40000000)) || a_cas(&m->_m_lock, old, tid)!=old)
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return EBUSY;
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m->_m_count = 1;
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if (m->_m_type < 4) return 0;
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if (m->_m_type >= 8) {
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@ -12,8 +12,8 @@ int pthread_mutex_unlock(pthread_mutex_t *m)
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self = __pthread_self();
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if ((m->_m_lock&0x1fffffff) != self->tid)
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return EPERM;
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if ((m->_m_type&3) == PTHREAD_MUTEX_RECURSIVE && --m->_m_count)
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return 0;
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if ((m->_m_type&3) == PTHREAD_MUTEX_RECURSIVE && m->_m_count)
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return m->_m_count--, 0;
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if (m->_m_type >= 4) {
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self->robust_list.pending = &m->_m_next;
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*(void **)m->_m_prev = m->_m_next;
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