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don't suppress sign output for NANs in printf 

formally, it seems a sign is only required when the '+' modifier
appears in the format specifier, in which case either '+' or '-' must
be present in the output. but the specification is written such that
an optional negative sign is part of the output format anyway, and the
simplest approach to fixing the problem is removing the code that was
suppressing the sign.
This commit is contained in:
Rich Felker 2014-12-18 17:41:34 -05:00
parent 2e1ae3b6b9
commit 0f859fc993
1 changed files with 1 additions and 1 deletions
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2
src/stdio/vfprintf.c
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@ -225,7 +225,7 @@ static int fmt_fp(FILE *f, long double y, int w, int p, int fl, int t)
if (!isfinite(y)) {
char *s = (t&32)?"inf":"INF";
if (y!=y) s=(t&32)?"nan":"NAN", pl=0;
if (y!=y) s=(t&32)?"nan":"NAN";
pad(f, ' ', w, 3+pl, fl&~ZERO_PAD);
out(f, prefix, pl);
out(f, s, 3);