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419a598eae
glibc-2.11 on x86_64 provides a machine-specific memchr() which is faster than the generic C implementation by around 40%, so let's make it possible to use it instead of the hand-coded version.
263 lines
7.5 KiB
C
263 lines
7.5 KiB
C
/*
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* fast fgets() replacement for log parsing
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*
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* Copyright 2000-2012 Willy Tarreau <w@1wt.eu>
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*
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* This library is free software; you can redistribute it and/or
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* modify it under the terms of the GNU Lesser General Public
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* License as published by the Free Software Foundation, version 2.1
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* exclusively.
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*
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* This library is distributed in the hope that it will be useful,
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* but WITHOUT ANY WARRANTY; without even the implied warranty of
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* MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the GNU
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* Lesser General Public License for more details.
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*
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* You should have received a copy of the GNU Lesser General Public License
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* along with this library; if not, write to the Free Software Foundation,
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* Inc., 51 Franklin Street, Fifth Floor, Boston, MA 02110-1301 USA
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*
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* This function manages its own buffer and returns a pointer to that buffer
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* in order to avoid expensive memory copies. It also checks for line breaks
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* 32 or 64 bits at a time. It could be improved a lot using mmap() but we
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* would not be allowed to replace trailing \n with zeroes and we would be
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* limited to small log files on 32-bit machines.
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*
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*/
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#include <stdlib.h>
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#include <string.h>
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#include <stdio.h>
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#include <unistd.h>
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#ifndef FGETS2_BUFSIZE
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#define FGETS2_BUFSIZE (256*1024)
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#endif
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/* return non-zero if the integer contains at least one zero byte */
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static inline unsigned int has_zero32(unsigned int x)
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{
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unsigned int y;
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/* Principle: we want to perform 4 tests on one 32-bit int at once. For
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* this, we have to simulate an SIMD instruction which we don't have by
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* default. The principle is that a zero byte is the only one which
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* will cause a 1 to appear on the upper bit of a byte/word/etc... when
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* we subtract 1. So we can detect a zero byte if a one appears at any
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* of the bits 7, 15, 23 or 31 where it was not. It takes only one
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* instruction to test for the presence of any of these bits, but it is
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* still complex to check for their initial absence. Thus, we'll
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* proceed differently : we first save and clear only those bits, then
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* we check in the final result if one of them is present and was not.
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* The order of operations below is important to save registers and
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* tests. The result is used as a boolean, so the last test must apply
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* on the constant so that it can efficiently be inlined.
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*/
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#if defined(__i386__)
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/* gcc on x86 loves copying registers over and over even on code that
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* simple, so let's do it by hand to prevent it from doing so :-(
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*/
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asm("lea -0x01010101(%0),%1\n"
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"not %0\n"
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"and %1,%0\n"
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: "=a" (x), "=r"(y)
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: "0" (x)
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);
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return x & 0x80808080;
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#else
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y = x - 0x01010101; /* generate a carry */
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x = ~x & y; /* clear the bits that were already set */
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return x & 0x80808080;
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#endif
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}
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/* return non-zero if the argument contains at least one zero byte. See principle above. */
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static inline unsigned long long has_zero64(unsigned long long x)
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{
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unsigned long long y;
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y = x - 0x0101010101010101ULL; /* generate a carry */
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y &= ~x; /* clear the bits that were already set */
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return y & 0x8080808080808080ULL;
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}
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static inline unsigned long has_zero(unsigned long x)
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{
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return (sizeof(x) == 8) ? has_zero64(x) : has_zero32(x);
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}
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/* find a '\n' between <next> and <end>. Warning: may read slightly past <end>.
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* If no '\n' is found, <end> is returned.
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*/
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static char *find_lf(char *next, char *end)
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{
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#if defined USE_MEMCHR
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/* some recent libc use platform-specific optimizations to provide more
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* efficient byte search than below (eg: glibc 2.11 on x86_64).
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*/
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next = memchr(next, '\n', end - next);
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if (!next)
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next = end;
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#else
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if (sizeof(long) == 4) { /* 32-bit system */
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/* this is a speed-up, we read 32 bits at once and check for an
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* LF character there. We stop if found then continue one at a
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* time.
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*/
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while (next < end && (((unsigned long)next) & 3) && *next != '\n')
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next++;
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/* Now next is multiple of 4 or equal to end. We know we can safely
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* read up to 32 bytes past end if needed because they're allocated.
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*/
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while (next < end) {
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if (has_zero32(*(unsigned int *)next ^ 0x0A0A0A0A))
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break;
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next += 4;
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if (has_zero32(*(unsigned int *)next ^ 0x0A0A0A0A))
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break;
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next += 4;
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if (has_zero32(*(unsigned int *)next ^ 0x0A0A0A0A))
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break;
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next += 4;
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if (has_zero32(*(unsigned int *)next ^ 0x0A0A0A0A))
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break;
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next += 4;
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if (has_zero32(*(unsigned int *)next ^ 0x0A0A0A0A))
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break;
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next += 4;
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if (has_zero32(*(unsigned int *)next ^ 0x0A0A0A0A))
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break;
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next += 4;
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if (has_zero32(*(unsigned int *)next ^ 0x0A0A0A0A))
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break;
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next += 4;
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if (has_zero32(*(unsigned int *)next ^ 0x0A0A0A0A))
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break;
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next += 4;
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}
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}
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else { /* 64-bit system */
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/* this is a speed-up, we read 64 bits at once and check for an
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* LF character there. We stop if found then continue one at a
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* time.
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*/
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if (next <= end) {
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/* max 3 bytes tested here */
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while ((((unsigned long)next) & 3) && *next != '\n')
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next++;
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/* maybe we have can skip 4 more bytes */
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if ((((unsigned long)next) & 4) && !has_zero32(*(unsigned int *)next ^ 0x0A0A0A0AU))
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next += 4;
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}
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/* now next is multiple of 8 or equal to end */
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while (next <= (end-68)) {
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if (has_zero64(*(unsigned long long *)next ^ 0x0A0A0A0A0A0A0A0AULL))
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break;
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next += 8;
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if (has_zero64(*(unsigned long long *)next ^ 0x0A0A0A0A0A0A0A0AULL))
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break;
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next += 8;
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if (has_zero64(*(unsigned long long *)next ^ 0x0A0A0A0A0A0A0A0AULL))
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break;
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next += 8;
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if (has_zero64(*(unsigned long long *)next ^ 0x0A0A0A0A0A0A0A0AULL))
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break;
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next += 8;
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if (has_zero64(*(unsigned long long *)next ^ 0x0A0A0A0A0A0A0A0AULL))
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break;
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next += 8;
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if (has_zero64(*(unsigned long long *)next ^ 0x0A0A0A0A0A0A0A0AULL))
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break;
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next += 8;
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if (has_zero64(*(unsigned long long *)next ^ 0x0A0A0A0A0A0A0A0AULL))
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break;
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next += 8;
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if (has_zero64(*(unsigned long long *)next ^ 0x0A0A0A0A0A0A0A0AULL))
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break;
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next += 8;
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}
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/* maybe we can skip 4 more bytes */
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if (!has_zero32(*(unsigned int *)next ^ 0x0A0A0A0AU))
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next += 4;
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}
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/* We finish if needed : if <next> is below <end>, it means we
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* found an LF in one of the 4 following bytes.
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*/
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while (next < end) {
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if (*next == '\n')
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break;
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next++;
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}
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#endif
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return next;
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}
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const char *fgets2(FILE *stream)
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{
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static char buffer[FGETS2_BUFSIZE + 68]; /* Note: +32 is enough on 32-bit systems */
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static char *end = buffer;
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static char *line = buffer;
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char *next;
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int ret;
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next = line;
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while (1) {
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next = find_lf(next, end);
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if (next < end) {
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const char *start = line;
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*next = '\0';
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line = next + 1;
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return start;
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}
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/* we found an incomplete line. First, let's move the
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* remaining part of the buffer to the beginning, then
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* try to complete the buffer with a new read. We can't
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* rely on <next> anymore because it went past <end>.
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*/
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if (line > buffer) {
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if (end != line)
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memmove(buffer, line, end - line);
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end = buffer + (end - line);
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next = end;
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line = buffer;
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} else {
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if (end == buffer + FGETS2_BUFSIZE)
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return NULL;
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}
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ret = read(fileno(stream), end, buffer + FGETS2_BUFSIZE - end);
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if (ret <= 0) {
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if (end == line)
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return NULL;
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*end = '\0';
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end = line; /* ensure we stop next time */
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return line;
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}
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end += ret;
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*end = '\n'; /* make parser stop ASAP */
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/* search for '\n' again */
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}
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}
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#ifdef BENCHMARK
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int main() {
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const char *p;
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unsigned int lines = 0;
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while ((p=fgets2(stdin)))
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lines++;
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printf("lines=%d\n", lines);
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return 0;
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}
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#endif
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