/* * Elastic Binary Trees - macros and structures for operations on 64bit nodes. * Version 6.0.6 * (C) 2002-2011 - Willy Tarreau * * This library is free software; you can redistribute it and/or * modify it under the terms of the GNU Lesser General Public * License as published by the Free Software Foundation, version 2.1 * exclusively. * * This library is distributed in the hope that it will be useful, * but WITHOUT ANY WARRANTY; without even the implied warranty of * MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the GNU * Lesser General Public License for more details. * * You should have received a copy of the GNU Lesser General Public * License along with this library; if not, write to the Free Software * Foundation, Inc., 51 Franklin Street, Fifth Floor, Boston, MA 02110-1301 USA */ #ifndef _EB64TREE_H #define _EB64TREE_H #include "ebtree.h" /* Return the structure of type whose member points to */ #define eb64_entry(ptr, type, member) container_of(ptr, type, member) #define EB64_ROOT EB_ROOT #define EB64_TREE_HEAD EB_TREE_HEAD /* These types may sometimes already be defined */ typedef unsigned long long u64; typedef signed long long s64; /* This structure carries a node, a leaf, and a key. It must start with the * eb_node so that it can be cast into an eb_node. We could also have put some * sort of transparent union here to reduce the indirection level, but the fact * is, the end user is not meant to manipulate internals, so this is pointless. * In case sizeof(void*)>=sizeof(u64), we know there will be some padding after * the key if it's unaligned. In this case we force the alignment on void* so * that we prefer to have the padding before for more efficient accesses. */ struct eb64_node { struct eb_node node; /* the tree node, must be at the beginning */ MAYBE_ALIGN(sizeof(u64)); ALWAYS_ALIGN(sizeof(void*)); u64 key; } ALIGNED(sizeof(void*)); /* * Exported functions and macros. * Many of them are always inlined because they are extremely small, and * are generally called at most once or twice in a program. */ /* Return leftmost node in the tree, or NULL if none */ static inline struct eb64_node *eb64_first(struct eb_root *root) { return eb64_entry(eb_first(root), struct eb64_node, node); } /* Return rightmost node in the tree, or NULL if none */ static inline struct eb64_node *eb64_last(struct eb_root *root) { return eb64_entry(eb_last(root), struct eb64_node, node); } /* Return next node in the tree, or NULL if none */ static inline struct eb64_node *eb64_next(struct eb64_node *eb64) { return eb64_entry(eb_next(&eb64->node), struct eb64_node, node); } /* Return previous node in the tree, or NULL if none */ static inline struct eb64_node *eb64_prev(struct eb64_node *eb64) { return eb64_entry(eb_prev(&eb64->node), struct eb64_node, node); } /* Return next leaf node within a duplicate sub-tree, or NULL if none. */ static inline struct eb64_node *eb64_next_dup(struct eb64_node *eb64) { return eb64_entry(eb_next_dup(&eb64->node), struct eb64_node, node); } /* Return previous leaf node within a duplicate sub-tree, or NULL if none. */ static inline struct eb64_node *eb64_prev_dup(struct eb64_node *eb64) { return eb64_entry(eb_prev_dup(&eb64->node), struct eb64_node, node); } /* Return next node in the tree, skipping duplicates, or NULL if none */ static inline struct eb64_node *eb64_next_unique(struct eb64_node *eb64) { return eb64_entry(eb_next_unique(&eb64->node), struct eb64_node, node); } /* Return previous node in the tree, skipping duplicates, or NULL if none */ static inline struct eb64_node *eb64_prev_unique(struct eb64_node *eb64) { return eb64_entry(eb_prev_unique(&eb64->node), struct eb64_node, node); } /* Delete node from the tree if it was linked in. Mark the node unused. Note * that this function relies on a non-inlined generic function: eb_delete. */ static inline void eb64_delete(struct eb64_node *eb64) { eb_delete(&eb64->node); } /* * The following functions are not inlined by default. They are declared * in eb64tree.c, which simply relies on their inline version. */ struct eb64_node *eb64_lookup(struct eb_root *root, u64 x); struct eb64_node *eb64i_lookup(struct eb_root *root, s64 x); struct eb64_node *eb64_lookup_le(struct eb_root *root, u64 x); struct eb64_node *eb64_lookup_ge(struct eb_root *root, u64 x); struct eb64_node *eb64_insert(struct eb_root *root, struct eb64_node *new); struct eb64_node *eb64i_insert(struct eb_root *root, struct eb64_node *new); /* * The following functions are less likely to be used directly, because their * code is larger. The non-inlined version is preferred. */ /* Delete node from the tree if it was linked in. Mark the node unused. */ static forceinline void __eb64_delete(struct eb64_node *eb64) { __eb_delete(&eb64->node); } /* * Find the first occurrence of a key in the tree . If none can be * found, return NULL. */ static forceinline struct eb64_node *__eb64_lookup(struct eb_root *root, u64 x) { struct eb64_node *node; eb_troot_t *troot; u64 y; troot = root->b[EB_LEFT]; if (unlikely(troot == NULL)) return NULL; while (1) { if ((eb_gettag(troot) == EB_LEAF)) { node = container_of(eb_untag(troot, EB_LEAF), struct eb64_node, node.branches); if (node->key == x) return node; else return NULL; } node = container_of(eb_untag(troot, EB_NODE), struct eb64_node, node.branches); y = node->key ^ x; if (!y) { /* Either we found the node which holds the key, or * we have a dup tree. In the later case, we have to * walk it down left to get the first entry. */ if (node->node.bit < 0) { troot = node->node.branches.b[EB_LEFT]; while (eb_gettag(troot) != EB_LEAF) troot = (eb_untag(troot, EB_NODE))->b[EB_LEFT]; node = container_of(eb_untag(troot, EB_LEAF), struct eb64_node, node.branches); } return node; } if ((y >> node->node.bit) >= EB_NODE_BRANCHES) return NULL; /* no more common bits */ troot = node->node.branches.b[(x >> node->node.bit) & EB_NODE_BRANCH_MASK]; } } /* * Find the first occurrence of a signed key in the tree . If none can * be found, return NULL. */ static forceinline struct eb64_node *__eb64i_lookup(struct eb_root *root, s64 x) { struct eb64_node *node; eb_troot_t *troot; u64 key = x ^ (1ULL << 63); u64 y; troot = root->b[EB_LEFT]; if (unlikely(troot == NULL)) return NULL; while (1) { if ((eb_gettag(troot) == EB_LEAF)) { node = container_of(eb_untag(troot, EB_LEAF), struct eb64_node, node.branches); if (node->key == (u64)x) return node; else return NULL; } node = container_of(eb_untag(troot, EB_NODE), struct eb64_node, node.branches); y = node->key ^ x; if (!y) { /* Either we found the node which holds the key, or * we have a dup tree. In the later case, we have to * walk it down left to get the first entry. */ if (node->node.bit < 0) { troot = node->node.branches.b[EB_LEFT]; while (eb_gettag(troot) != EB_LEAF) troot = (eb_untag(troot, EB_NODE))->b[EB_LEFT]; node = container_of(eb_untag(troot, EB_LEAF), struct eb64_node, node.branches); } return node; } if ((y >> node->node.bit) >= EB_NODE_BRANCHES) return NULL; /* no more common bits */ troot = node->node.branches.b[(key >> node->node.bit) & EB_NODE_BRANCH_MASK]; } } /* Insert eb64_node into subtree starting at node root . * Only new->key needs be set with the key. The eb64_node is returned. * If root->b[EB_RGHT]==1, the tree may only contain unique keys. */ static forceinline struct eb64_node * __eb64_insert(struct eb_root *root, struct eb64_node *new) { struct eb64_node *old; unsigned int side; eb_troot_t *troot; u64 newkey; /* caching the key saves approximately one cycle */ eb_troot_t *root_right; int old_node_bit; side = EB_LEFT; troot = root->b[EB_LEFT]; root_right = root->b[EB_RGHT]; if (unlikely(troot == NULL)) { /* Tree is empty, insert the leaf part below the left branch */ root->b[EB_LEFT] = eb_dotag(&new->node.branches, EB_LEAF); new->node.leaf_p = eb_dotag(root, EB_LEFT); new->node.node_p = NULL; /* node part unused */ return new; } /* The tree descent is fairly easy : * - first, check if we have reached a leaf node * - second, check if we have gone too far * - third, reiterate * Everywhere, we use for the node node we are inserting, * for the node we attach it to, and for the node we are * displacing below . will always point to the future node * (tagged with its type). carries the side the node is * attached to below its parent, which is also where previous node * was attached. carries the key being inserted. */ newkey = new->key; while (1) { if (unlikely(eb_gettag(troot) == EB_LEAF)) { eb_troot_t *new_left, *new_rght; eb_troot_t *new_leaf, *old_leaf; old = container_of(eb_untag(troot, EB_LEAF), struct eb64_node, node.branches); new_left = eb_dotag(&new->node.branches, EB_LEFT); new_rght = eb_dotag(&new->node.branches, EB_RGHT); new_leaf = eb_dotag(&new->node.branches, EB_LEAF); old_leaf = eb_dotag(&old->node.branches, EB_LEAF); new->node.node_p = old->node.leaf_p; /* Right here, we have 3 possibilities : - the tree does not contain the key, and we have new->key < old->key. We insert new above old, on the left ; - the tree does not contain the key, and we have new->key > old->key. We insert new above old, on the right ; - the tree does contain the key, which implies it is alone. We add the new key next to it as a first duplicate. The last two cases can easily be partially merged. */ if (new->key < old->key) { new->node.leaf_p = new_left; old->node.leaf_p = new_rght; new->node.branches.b[EB_LEFT] = new_leaf; new->node.branches.b[EB_RGHT] = old_leaf; } else { /* we may refuse to duplicate this key if the tree is * tagged as containing only unique keys. */ if ((new->key == old->key) && eb_gettag(root_right)) return old; /* new->key >= old->key, new goes the right */ old->node.leaf_p = new_left; new->node.leaf_p = new_rght; new->node.branches.b[EB_LEFT] = old_leaf; new->node.branches.b[EB_RGHT] = new_leaf; if (new->key == old->key) { new->node.bit = -1; root->b[side] = eb_dotag(&new->node.branches, EB_NODE); return new; } } break; } /* OK we're walking down this link */ old = container_of(eb_untag(troot, EB_NODE), struct eb64_node, node.branches); old_node_bit = old->node.bit; /* Stop going down when we don't have common bits anymore. We * also stop in front of a duplicates tree because it means we * have to insert above. */ if ((old_node_bit < 0) || /* we're above a duplicate tree, stop here */ (((new->key ^ old->key) >> old_node_bit) >= EB_NODE_BRANCHES)) { /* The tree did not contain the key, so we insert before the node * , and set ->bit to designate the lowest bit position in * which applies to ->branches.b[]. */ eb_troot_t *new_left, *new_rght; eb_troot_t *new_leaf, *old_node; new_left = eb_dotag(&new->node.branches, EB_LEFT); new_rght = eb_dotag(&new->node.branches, EB_RGHT); new_leaf = eb_dotag(&new->node.branches, EB_LEAF); old_node = eb_dotag(&old->node.branches, EB_NODE); new->node.node_p = old->node.node_p; if (new->key < old->key) { new->node.leaf_p = new_left; old->node.node_p = new_rght; new->node.branches.b[EB_LEFT] = new_leaf; new->node.branches.b[EB_RGHT] = old_node; } else if (new->key > old->key) { old->node.node_p = new_left; new->node.leaf_p = new_rght; new->node.branches.b[EB_LEFT] = old_node; new->node.branches.b[EB_RGHT] = new_leaf; } else { struct eb_node *ret; ret = eb_insert_dup(&old->node, &new->node); return container_of(ret, struct eb64_node, node); } break; } /* walk down */ root = &old->node.branches; if (sizeof(long) >= 8) { side = newkey >> old_node_bit; } else { /* note: provides the best code on low-register count archs * such as i386. */ side = newkey; side >>= old_node_bit; if (old_node_bit >= 32) { side = newkey >> 32; side >>= old_node_bit & 0x1F; } } side &= EB_NODE_BRANCH_MASK; troot = root->b[side]; } /* Ok, now we are inserting between and . 's * parent is already set to , and the 's branch is still in * . Update the root's leaf till we have it. Note that we can also * find the side by checking the side of new->node.node_p. */ /* We need the common higher bits between new->key and old->key. * What differences are there between new->key and the node here ? * NOTE that bit(new) is always < bit(root) because highest * bit of new->key and old->key are identical here (otherwise they * would sit on different branches). */ // note that if EB_NODE_BITS > 1, we should check that it's still >= 0 new->node.bit = fls64(new->key ^ old->key) - EB_NODE_BITS; root->b[side] = eb_dotag(&new->node.branches, EB_NODE); return new; } /* Insert eb64_node into subtree starting at node root , using * signed keys. Only new->key needs be set with the key. The eb64_node * is returned. If root->b[EB_RGHT]==1, the tree may only contain unique keys. */ static forceinline struct eb64_node * __eb64i_insert(struct eb_root *root, struct eb64_node *new) { struct eb64_node *old; unsigned int side; eb_troot_t *troot; u64 newkey; /* caching the key saves approximately one cycle */ eb_troot_t *root_right; int old_node_bit; side = EB_LEFT; troot = root->b[EB_LEFT]; root_right = root->b[EB_RGHT]; if (unlikely(troot == NULL)) { /* Tree is empty, insert the leaf part below the left branch */ root->b[EB_LEFT] = eb_dotag(&new->node.branches, EB_LEAF); new->node.leaf_p = eb_dotag(root, EB_LEFT); new->node.node_p = NULL; /* node part unused */ return new; } /* The tree descent is fairly easy : * - first, check if we have reached a leaf node * - second, check if we have gone too far * - third, reiterate * Everywhere, we use for the node node we are inserting, * for the node we attach it to, and for the node we are * displacing below . will always point to the future node * (tagged with its type). carries the side the node is * attached to below its parent, which is also where previous node * was attached. carries a high bit shift of the key being * inserted in order to have negative keys stored before positive * ones. */ newkey = new->key ^ (1ULL << 63); while (1) { if (unlikely(eb_gettag(troot) == EB_LEAF)) { eb_troot_t *new_left, *new_rght; eb_troot_t *new_leaf, *old_leaf; old = container_of(eb_untag(troot, EB_LEAF), struct eb64_node, node.branches); new_left = eb_dotag(&new->node.branches, EB_LEFT); new_rght = eb_dotag(&new->node.branches, EB_RGHT); new_leaf = eb_dotag(&new->node.branches, EB_LEAF); old_leaf = eb_dotag(&old->node.branches, EB_LEAF); new->node.node_p = old->node.leaf_p; /* Right here, we have 3 possibilities : - the tree does not contain the key, and we have new->key < old->key. We insert new above old, on the left ; - the tree does not contain the key, and we have new->key > old->key. We insert new above old, on the right ; - the tree does contain the key, which implies it is alone. We add the new key next to it as a first duplicate. The last two cases can easily be partially merged. */ if ((s64)new->key < (s64)old->key) { new->node.leaf_p = new_left; old->node.leaf_p = new_rght; new->node.branches.b[EB_LEFT] = new_leaf; new->node.branches.b[EB_RGHT] = old_leaf; } else { /* we may refuse to duplicate this key if the tree is * tagged as containing only unique keys. */ if ((new->key == old->key) && eb_gettag(root_right)) return old; /* new->key >= old->key, new goes the right */ old->node.leaf_p = new_left; new->node.leaf_p = new_rght; new->node.branches.b[EB_LEFT] = old_leaf; new->node.branches.b[EB_RGHT] = new_leaf; if (new->key == old->key) { new->node.bit = -1; root->b[side] = eb_dotag(&new->node.branches, EB_NODE); return new; } } break; } /* OK we're walking down this link */ old = container_of(eb_untag(troot, EB_NODE), struct eb64_node, node.branches); old_node_bit = old->node.bit; /* Stop going down when we don't have common bits anymore. We * also stop in front of a duplicates tree because it means we * have to insert above. */ if ((old_node_bit < 0) || /* we're above a duplicate tree, stop here */ (((new->key ^ old->key) >> old_node_bit) >= EB_NODE_BRANCHES)) { /* The tree did not contain the key, so we insert before the node * , and set ->bit to designate the lowest bit position in * which applies to ->branches.b[]. */ eb_troot_t *new_left, *new_rght; eb_troot_t *new_leaf, *old_node; new_left = eb_dotag(&new->node.branches, EB_LEFT); new_rght = eb_dotag(&new->node.branches, EB_RGHT); new_leaf = eb_dotag(&new->node.branches, EB_LEAF); old_node = eb_dotag(&old->node.branches, EB_NODE); new->node.node_p = old->node.node_p; if ((s64)new->key < (s64)old->key) { new->node.leaf_p = new_left; old->node.node_p = new_rght; new->node.branches.b[EB_LEFT] = new_leaf; new->node.branches.b[EB_RGHT] = old_node; } else if ((s64)new->key > (s64)old->key) { old->node.node_p = new_left; new->node.leaf_p = new_rght; new->node.branches.b[EB_LEFT] = old_node; new->node.branches.b[EB_RGHT] = new_leaf; } else { struct eb_node *ret; ret = eb_insert_dup(&old->node, &new->node); return container_of(ret, struct eb64_node, node); } break; } /* walk down */ root = &old->node.branches; if (sizeof(long) >= 8) { side = newkey >> old_node_bit; } else { /* note: provides the best code on low-register count archs * such as i386. */ side = newkey; side >>= old_node_bit; if (old_node_bit >= 32) { side = newkey >> 32; side >>= old_node_bit & 0x1F; } } side &= EB_NODE_BRANCH_MASK; troot = root->b[side]; } /* Ok, now we are inserting between and . 's * parent is already set to , and the 's branch is still in * . Update the root's leaf till we have it. Note that we can also * find the side by checking the side of new->node.node_p. */ /* We need the common higher bits between new->key and old->key. * What differences are there between new->key and the node here ? * NOTE that bit(new) is always < bit(root) because highest * bit of new->key and old->key are identical here (otherwise they * would sit on different branches). */ // note that if EB_NODE_BITS > 1, we should check that it's still >= 0 new->node.bit = fls64(new->key ^ old->key) - EB_NODE_BITS; root->b[side] = eb_dotag(&new->node.branches, EB_NODE); return new; } #endif /* _EB64_TREE_H */