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CLEANUP: pattern: rename pat_ref_commit() to pat_ref_commit_elt()
It's about the third time I get confused by these functions, half of which manipulate the reference as a whole and those manipulating only an entry. For me "pat_ref_commit" means committing the pattern reference, not just an element, so let's rename it. A number of other ones should really be renamed before 2.4 gets released :-/
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@ -191,7 +191,7 @@ int pat_ref_delete(struct pat_ref *ref, const char *key);
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void pat_ref_delete_by_ptr(struct pat_ref *ref, struct pat_ref_elt *elt);
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int pat_ref_delete_by_id(struct pat_ref *ref, struct pat_ref_elt *refelt);
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int pat_ref_prune(struct pat_ref *ref);
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int pat_ref_commit(struct pat_ref *ref, struct pat_ref_elt *elt, char **err);
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int pat_ref_commit_elt(struct pat_ref *ref, struct pat_ref_elt *elt, char **err);
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int pat_ref_purge_older(struct pat_ref *ref, unsigned int oldest, int budget);
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void pat_ref_reload(struct pat_ref *ref, struct pat_ref *replace);
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@ -1965,7 +1965,7 @@ int pat_ref_push(struct pat_ref_elt *elt, struct pattern_expr *expr,
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* pointer <err> may have been updated (and the caller must free it). Failure
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* causes include memory allocation, parsing error or indexing error.
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*/
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int pat_ref_commit(struct pat_ref *ref, struct pat_ref_elt *elt, char **err)
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int pat_ref_commit_elt(struct pat_ref *ref, struct pat_ref_elt *elt, char **err)
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{
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struct pattern_expr *expr;
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@ -1996,7 +1996,7 @@ struct pat_ref_elt *pat_ref_load(struct pat_ref *ref, unsigned int gen,
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elt = pat_ref_append(ref, pattern, sample, line);
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if (elt) {
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elt->gen_id = gen;
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if (!pat_ref_commit(ref, elt, err))
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if (!pat_ref_commit_elt(ref, elt, err))
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elt = NULL;
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} else
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memprintf(err, "out of memory error");
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