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fftools/sync_queue: document overall design
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@ -28,6 +28,41 @@
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#include "objpool.h"
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#include "sync_queue.h"
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/*
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* How this works:
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* --------------
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* time: 0 1 2 3 4 5 6 7 8 9 10 11 12 13
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* -------------------------------------------------------------------
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* | | | | | | | | | | | | | |
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* | ┌───┐┌────────┐┌───┐┌─────────────┐
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* stream 0| │d=1││ d=2 ││d=1││ d=3 │
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* | └───┘└────────┘└───┘└─────────────┘
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* ┌───┐ ┌───────────────────────┐
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* stream 1│d=1│ │ d=5 │
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* └───┘ └───────────────────────┘
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* | ┌───┐┌───┐┌───┐┌───┐
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* stream 2| │d=1││d=1││d=1││d=1│ <- stream 2 is the head stream of the queue
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* | └───┘└───┘└───┘└───┘
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* ^ ^
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* [stream 2 tail] [stream 2 head]
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*
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* We have N streams (N=3 in the diagram), each stream is a FIFO. The *tail* of
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* each FIFO is the frame with smallest end time, the *head* is the frame with
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* the largest end time. Frames submitted to the queue with sq_send() are placed
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* after the head, frames returned to the caller with sq_receive() are taken
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* from the tail.
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*
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* The head stream of the whole queue (SyncQueue.head_stream) is the limiting
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* stream with the *smallest* head timestamp, i.e. the stream whose source lags
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* furthest behind all other streams. It determines which frames can be output
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* from the queue.
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*
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* In the diagram, the head stream is 2, because it head time is t=5, while
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* streams 0 and 1 end at t=8 and t=9 respectively. All frames that _end_ at
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* or before t=5 can be output, i.e. the first 3 frames from stream 0, first
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* frame from stream 1, and all 4 frames from stream 2.
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*/
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typedef struct SyncQueueStream {
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AVFifo *fifo;
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AVRational tb;
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@ -38,6 +38,11 @@ typedef union SyncQueueFrame {
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#define SQFRAME(frame) ((SyncQueueFrame){ .f = (frame) })
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#define SQPKT(pkt) ((SyncQueueFrame){ .p = (pkt) })
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/**
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* A sync queue provides timestamp synchronization between multiple streams.
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* Some of these streams are marked as "limiting", then the queue ensures no
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* stream gets ahead of any of the limiting streams.
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*/
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typedef struct SyncQueue SyncQueue;
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/**
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