avcodec/h264idct_template: Fix integer overflow in ff_h264_idct8_add()

Fixes: 2891/clusterfuzz-testcase-minimized-5881795457318912
Fixes: runtime error: signed integer overflow: 1551827968 - -775913984 cannot be represented in type 'int'

Found-by: continuous fuzzing process https://github.com/google/oss-fuzz/tree/master/projects/ffmpeg
Signed-off-by: Michael Niedermayer <michael@niedermayer.cc>
This commit is contained in:
Michael Niedermayer 2017-08-17 01:06:14 +02:00
parent 429f3266c1
commit 6def8b8d92
1 changed files with 12 additions and 12 deletions

View File

@ -76,20 +76,20 @@ void FUNCC(ff_h264_idct8_add)(uint8_t *_dst, int16_t *_block, int stride){
for( i = 0; i < 8; i++ )
{
const int a0 = block[i+0*8] + block[i+4*8];
const int a2 = block[i+0*8] - block[i+4*8];
const int a4 = (block[i+2*8]>>1) - block[i+6*8];
const int a6 = (block[i+6*8]>>1) + block[i+2*8];
const unsigned int a0 = block[i+0*8] + block[i+4*8];
const unsigned int a2 = block[i+0*8] - block[i+4*8];
const unsigned int a4 = (block[i+2*8]>>1) - block[i+6*8];
const unsigned int a6 = (block[i+6*8]>>1) + block[i+2*8];
const int b0 = a0 + a6;
const int b2 = a2 + a4;
const int b4 = a2 - a4;
const int b6 = a0 - a6;
const unsigned int b0 = a0 + a6;
const unsigned int b2 = a2 + a4;
const unsigned int b4 = a2 - a4;
const unsigned int b6 = a0 - a6;
const int a1 = -block[i+3*8] + block[i+5*8] - block[i+7*8] - (block[i+7*8]>>1);
const int a3 = block[i+1*8] + block[i+7*8] - block[i+3*8] - (block[i+3*8]>>1);
const int a5 = -block[i+1*8] + block[i+7*8] + block[i+5*8] + (block[i+5*8]>>1);
const int a7 = block[i+3*8] + block[i+5*8] + block[i+1*8] + (block[i+1*8]>>1);
const int a1 = -block[i+3*8] + (unsigned)block[i+5*8] - block[i+7*8] - (block[i+7*8]>>1);
const int a3 = block[i+1*8] + (unsigned)block[i+7*8] - block[i+3*8] - (block[i+3*8]>>1);
const int a5 = -block[i+1*8] + (unsigned)block[i+7*8] + block[i+5*8] + (block[i+5*8]>>1);
const int a7 = block[i+3*8] + (unsigned)block[i+5*8] + block[i+1*8] + (block[i+1*8]>>1);
const int b1 = (a7>>2) + a1;
const int b3 = a3 + (a5>>2);