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btrfs-progs: remove useless branch in __merge_refs

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After call of ref_for_same_block, ref1->parent must equals to
ref2->parent, the block of exchange is never reached.

So remove the block of exchange.

Signed-off-by: Su Yue <suy.fnst@cn.fujitsu.com>
Reviewed-by: Qu Wenruo <wqu@suse.com>
Signed-off-by: David Sterba <dsterba@suse.com>
This commit is contained in:
Su Yue 2018-04-24 13:52:32 +08:00 committed by David Sterba
parent 6a42806d74
commit d9b32dd2e9
1 changed files with 0 additions and 6 deletions
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6
backref.c
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@ -497,7 +497,6 @@ static void __merge_refs(struct pref_state *prefstate, int mode)
for (pos2 = pos1->next, n2 = pos2->next; pos2 != head; for (pos2 = pos1->next, n2 = pos2->next; pos2 != head;
pos2 = n2, n2 = pos2->next) { pos2 = n2, n2 = pos2->next) {
struct __prelim_ref *ref2; struct __prelim_ref *ref2;
struct __prelim_ref *xchg;
struct extent_inode_elem *eie; struct extent_inode_elem *eie;
ref2 = list_entry(pos2, struct __prelim_ref, list); ref2 = list_entry(pos2, struct __prelim_ref, list);
@ -505,11 +504,6 @@ static void __merge_refs(struct pref_state *prefstate, int mode)
if (mode == 1) { if (mode == 1) {
if (!ref_for_same_block(ref1, ref2)) if (!ref_for_same_block(ref1, ref2))
continue; continue;
if (!ref1->parent && ref2->parent) {
xchg = ref1;
ref1 = ref2;
ref2 = xchg;
}
} else { } else {
if (ref1->parent != ref2->parent) if (ref1->parent != ref2->parent)
continue; continue;