btrfs-progs: fi usage: support mixed blockgroups
Properly account the duplicated block groups and global reserve. Bugzilla: https://bugzilla.kernel.org/show_bug.cgi?id=110111 Reported-by: Chris Murphy <bugzilla@colorremedies.com> Signed-off-by: David Sterba <dsterba@suse.com>
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@ -337,6 +337,7 @@ static int print_filesystem_usage_overall(int fd, struct chunk_info *chunkinfo,
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u64 free_estimated = 0;
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u64 free_min = 0;
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int max_data_ratio = 1;
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int mixed = 0;
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sargs = load_space_info(fd, path);
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if (!sargs) {
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@ -394,10 +395,9 @@ static int print_filesystem_usage_overall(int fd, struct chunk_info *chunkinfo,
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l_global_reserve_used = sargs->spaces[i].used_bytes;
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}
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if ((flags & (BTRFS_BLOCK_GROUP_DATA | BTRFS_BLOCK_GROUP_METADATA))
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== (BTRFS_BLOCK_GROUP_DATA | BTRFS_BLOCK_GROUP_METADATA)) {
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warning("MIXED blockgroups not handled");
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== (BTRFS_BLOCK_GROUP_DATA | BTRFS_BLOCK_GROUP_METADATA)) {
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mixed = 1;
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}
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if (flags & BTRFS_BLOCK_GROUP_DATA) {
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r_data_used += sargs->spaces[i].used_bytes * ratio;
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r_data_chunks += sargs->spaces[i].total_bytes * ratio;
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@ -414,13 +414,20 @@ static int print_filesystem_usage_overall(int fd, struct chunk_info *chunkinfo,
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}
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}
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r_total_chunks = r_data_chunks + r_metadata_chunks + r_system_chunks;
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r_total_used = r_data_used + r_metadata_used + r_system_used;
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r_total_chunks = r_data_chunks + r_system_chunks;
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r_total_used = r_data_used + r_system_used;
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if (!mixed) {
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r_total_chunks += r_metadata_chunks;
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r_total_used += r_metadata_used;
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}
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r_total_unused = r_total_size - r_total_chunks;
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/* Raw / Logical = raid factor, >= 1 */
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data_ratio = (double)r_data_chunks / l_data_chunks;
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metadata_ratio = (double)r_metadata_chunks / l_metadata_chunks;
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if (mixed)
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metadata_ratio = data_ratio;
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else
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metadata_ratio = (double)r_metadata_chunks / l_metadata_chunks;
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#if 0
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/* add the raid5/6 allocated space */
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@ -437,6 +444,13 @@ static int print_filesystem_usage_overall(int fd, struct chunk_info *chunkinfo,
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* In non-mixed case there's no difference.
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*/
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free_estimated = (r_data_chunks - r_data_used) / data_ratio;
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/*
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* For mixed-bg the metadata are left out in calculations thus global
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* reserve would be lost. Part of it could be permanently allocated,
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* we have to subtract the used bytes so we don't go under zero free.
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*/
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if (mixed)
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free_estimated -= l_global_reserve - l_global_reserve_used;
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free_min = free_estimated;
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/* Chop unallocatable space */
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