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Implement strmem() and use it in join(1)
We want our delimiters to also contain 0 characters and have them handled gracefully. To accomplish this, I wrote a function strmem(), which looks for a certain, arbitrarily long memory subset in a given string. memmem() is a GNU extension and forces you to call strlen every time.
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1
Makefile
1
Makefile
@ -75,6 +75,7 @@ LIBUTILSRC =\
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libutil/strcasestr.c\
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libutil/strlcat.c\
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libutil/strlcpy.c\
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libutil/strmem.c\
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libutil/strsep.c\
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libutil/strtonum.c\
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libutil/unescape.c
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2
join.c
2
join.c
@ -225,7 +225,7 @@ makeline(char *s, size_t len)
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beg = sp;
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if (sep) {
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if (!(end = utfutf(sp, sep)))
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if (!(end = strmem(sp, sep, seplen)))
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eol = 1;
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if (!eol) {
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23
libutil/strmem.c
Normal file
23
libutil/strmem.c
Normal file
@ -0,0 +1,23 @@
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/* See LICENSE file for copyright and license details. */
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#include <stddef.h>
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#include <string.h>
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char *
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strmem(char *haystack, char *needle, size_t needlelen)
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{
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size_t i;
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for (i = 0; i < needlelen; i++) {
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if (haystack[i] == '\0') {
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return NULL;
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}
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}
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for (; haystack[i]; i++) {
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if (!(memcmp(haystack + i - needlelen, needle, needlelen))) {
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return (haystack + i - needlelen);
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}
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}
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return NULL;
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}
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