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Improve readability of ConditionalExpression rendering code.

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This commit is contained in:
Chris PeBenito 2015-02-14 17:17:52 -05:00
parent 2f44b599ca
commit 7bacae7596
1 changed files with 13 additions and 17 deletions

30
setools/policyrep/boolcond.py
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@ -1,4 +1,4 @@
# Copyright 2014, Tresys Technology, LLC
# Copyright 2014-2015, Tresys Technology, LLC
#
# This file is part of SETools.
#
@ -98,7 +98,7 @@ class ConditionalExpr(symbol.PolicySymbol):
# highest precedence (NOT) so if there is a single binary
# operator, no parentheses are output
stack = []
prev_oper = qpol.QPOL_COND_EXPR_NOT
prev_op_precedence = self._cond_expr_val_to_precedence[qpol.QPOL_COND_EXPR_NOT]
for expr_node in self.qpol_symbol.expr_node_iter(self.policy):
expr_node_type = expr_node.expr_type(self.policy)
@ -109,37 +109,33 @@ class ConditionalExpr(symbol.PolicySymbol):
stack.append(str(nodebool))
elif expr_node_type == qpol.QPOL_COND_EXPR_NOT: # unary operator
operand = stack.pop()
operator = self._cond_expr_val_to_text[expr_node_type]
op_precedence = self._cond_expr_val_to_precedence[expr_node_type]
# NOT is the highest precedence, so only need
# parentheses if the operand is a subexpression
if isinstance(operand, list):
subexpr = [
self._cond_expr_val_to_text[expr_node_type],
"(", operand, ")"]
subexpr = [operator, "(", operand, ")"]
else:
subexpr = [
self._cond_expr_val_to_text[expr_node_type], operand]
subexpr = [operator, operand]
stack.append(subexpr)
prev_oper = expr_node_type
prev_op_precedence = op_precedence
else:
operand1 = stack.pop()
operand2 = stack.pop()
operator = self._cond_expr_val_to_text[expr_node_type]
op_precedence = self._cond_expr_val_to_precedence[expr_node_type]
if self._cond_expr_val_to_precedence[prev_oper] > \
self._cond_expr_val_to_precedence[expr_node_type]:
if prev_op_precedence > op_precedence:
# if previous operator is of higher precedence
# no parentheses are needed.
subexpr = [
operand1, self._cond_expr_val_to_text[expr_node_type],
operand2]
subexpr = [operand1, operator, operand2]
else:
subexpr = ["(", operand1,
self._cond_expr_val_to_text[expr_node_type],
operand2, ")"]
subexpr = ["(", operand1, operator, operand2, ")"]
stack.append(subexpr)
prev_oper = expr_node_type
prev_op_precedence = op_precedence
return self.__unwind_subexpression(stack)