Fix evaluation of expressions of the form: E1;E2.

The pointer to the char ';' has to be increased before to evaluate
";E2".

Originally committed as revision 25623 to svn://svn.ffmpeg.org/ffmpeg/trunk
This commit is contained in:
Stefano Sabatini 2010-11-01 09:34:12 +00:00
parent d56920e206
commit 63b1630356
2 changed files with 3 additions and 2 deletions

View File

@ -41,7 +41,7 @@
#define LIBAVUTIL_VERSION_MAJOR 50
#define LIBAVUTIL_VERSION_MINOR 32
#define LIBAVUTIL_VERSION_MICRO 3
#define LIBAVUTIL_VERSION_MICRO 4
#define LIBAVUTIL_VERSION_INT AV_VERSION_INT(LIBAVUTIL_VERSION_MAJOR, \
LIBAVUTIL_VERSION_MINOR, \

View File

@ -404,12 +404,12 @@ static int parse_expr(AVExpr **e, Parser *p)
if ((ret = parse_subexpr(&e0, p)) < 0)
return ret;
while (*p->s == ';') {
p->s++;
e1 = e0;
if ((ret = parse_subexpr(&e2, p)) < 0) {
av_free_expr(e1);
return ret;
}
p->s++;
e0 = new_eval_expr(e_last, 1, e1, e2);
if (!e0) {
av_free_expr(e1);
@ -534,6 +534,7 @@ int main(void)
double d;
const char **expr, *exprs[] = {
"",
"1;2",
"1+(5-2)^(3-1)+1/2+sin(PI)-max(-2.2,-3.1)",
"80G/80Gi"
"1k",