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avutil/parseutils: fix some overflows in duration calculations 

Also properly return AVERROR(ERANGE) in case of actual overflows.

Signed-off-by: Marton Balint <cus@passwd.hu>
This commit is contained in:
Marton Balint 2018-09-30 22:34:41 +02:00
parent d40dc64173
commit 4c777d52b9
1 changed files with 10 additions and 4 deletions
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14
libavutil/parseutils.c
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@ -661,12 +661,15 @@ int av_parse_time(int64_t *timeval, const char *timestr, int duration)
if (!q) {
char *o;
/* parse timestr as S+ */
dt.tm_sec = strtol(p, &o, 10);
errno = 0;
t = strtoll(p, &o, 10);
if (o == p) /* the parsing didn't succeed */
return AVERROR(EINVAL);
dt.tm_min = 0;
dt.tm_hour = 0;
if (errno == ERANGE)
return AVERROR(ERANGE);
q = o;
} else {
t = dt.tm_hour * 3600 + dt.tm_min * 60 + dt.tm_sec;
}
}
@ -688,7 +691,6 @@ int av_parse_time(int64_t *timeval, const char *timestr, int duration)
}
if (duration) {
t = dt.tm_hour * 3600 + dt.tm_min * 60 + dt.tm_sec;
if (q[0] == 'm' && q[1] == 's') {
suffix = 1000;
microseconds /= 1000;
@ -734,7 +736,11 @@ int av_parse_time(int64_t *timeval, const char *timestr, int duration)
if (*q)
return AVERROR(EINVAL);
if (INT64_MAX / suffix < t)
return AVERROR(ERANGE);
t *= suffix;
if (INT64_MAX - microseconds < t)
return AVERROR(ERANGE);
t += microseconds;
*timeval = negative ? -t : t;
return 0;