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dump_stream: print the timebase as is, do not reduce it 

It makes more sense to print the timebase exactly as it is set. Also,
this avoids a divide by zero when av_dump_format() is called on a format
context before writing the header.
This commit is contained in:
Anton Khirnov 2014-06-24 07:39:35 +02:00
parent 1b04eb20f7
commit 3f4edf0125
1 changed files with 1 additions and 2 deletions
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3
libavformat/dump.c
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@ -279,7 +279,6 @@ static void dump_stream_format(AVFormatContext *ic, int i,
char buf[256];
int flags = (is_output ? ic->oformat->flags : ic->iformat->flags);
AVStream *st = ic->streams[i];
int g = av_gcd(st->time_base.num, st->time_base.den);
AVDictionaryEntry *lang = av_dict_get(st->metadata, "language", NULL, 0);
avcodec_string(buf, sizeof(buf), st->codec, is_output);
@ -292,7 +291,7 @@ static void dump_stream_format(AVFormatContext *ic, int i,
if (lang)
av_log(NULL, AV_LOG_INFO, "(%s)", lang->value);
av_log(NULL, AV_LOG_DEBUG, ", %d, %d/%d", st->codec_info_nb_frames,
st->time_base.num / g, st->time_base.den / g);
st->time_base.num, st->time_base.den);
av_log(NULL, AV_LOG_INFO, ": %s", buf);
if (st->sample_aspect_ratio.num && // default